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Grade: 12

                        

31 question......................................... ......................

11 months ago

Answers : (3)

Arun
25141 Points
							
 

Let acceleration of lift be a.

acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the lift

Or, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]

displacement s = 6 ft.

time taken t = 1 s.

initial velocity u = 0

s = ut + 1/2 at^2 = 0*1 + 1/2 (32-a)*1*1 = 1/2 (32-a)

Therefore, 6 = 1/2 (32-a)

Hence a = 20 ft./s^2

 

Tha ks and regards

11 months ago
Vikas TU
13786 Points
							
Dear student 
Please fllow th below link 
Good Luck 
11 months ago
aswanth nayak
100 Points
							
 
Dear student 
Please fllow th below link 
Good Luck 
8 months ago
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