31 question...............................................................
31 question.........................................
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sri harshitha honey , 6 Years ago
Grade 12
Mechanics> 31 question.................................
3 Answers
Arun
Let acceleration of lift be a.
acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the lift
Or, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]
displacement s = 6 ft.
time taken t = 1 s.
initial velocity u = 0
s = ut + 1/2 at^2 = 0*1 + 1/2 (32-a)*1*1 = 1/2 (32-a)
Therefore, 6 = 1/2 (32-a)
Hence a = 20 ft./s^2
Tha ks and regards
Approved Last Activity: 6 Years ago
Vikas TU
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aswanth nayak
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