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31 question......................................... ......................

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11 months ago

Arun
25141 Points
```							 Let acceleration of lift be a.acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the liftOr, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]displacement s = 6 ft.time taken t = 1 s.initial velocity u = 0s = ut + 1/2 at^2 = 0*1 + 1/2 (32-a)*1*1 = 1/2 (32-a)Therefore, 6 = 1/2 (32-a)Hence a = 20 ft./s^2 Tha ks and regards
```
11 months ago
Vikas TU
13786 Points
```							Dear student Please fllow th below link https://www.askiitians.com/forums/Mechanics/10/4090/question.htmGood Luck
```
11 months ago
aswanth nayak
100 Points
```							 Dear student Please fllow th below link https://www.askiitians.com/forums/Mechanics/10/4090/question.htmGood Luck
```
8 months ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions