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Grade: 12
        
31 question.........................................
......................
3 months ago

Answers : (3)

Arun
23760 Points
							
 

Let acceleration of lift be a.

acceleration of ball with respect to the lift = acceleration of ball with respesct to ground - acceleration of the lift

Or, aball(lift) = g - a = 9.8 m/s^2 - a = 32 ft./s^2 - a [ 9.8m = 32 ft. ]

displacement s = 6 ft.

time taken t = 1 s.

initial velocity u = 0

s = ut + 1/2 at^2 = 0*1 + 1/2 (32-a)*1*1 = 1/2 (32-a)

Therefore, 6 = 1/2 (32-a)

Hence a = 20 ft./s^2

 

Tha ks and regards

3 months ago
Vikas TU
10469 Points
							
Dear student 
Please fllow th below link 
Good Luck 
3 months ago
aswanth nayak
100 Points
							
 
Dear student 
Please fllow th below link 
Good Luck 
28 days ago
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