Arun
Last Activity: 4 Years ago
A charged particle charge Q = 2 × 10^-6C and mass m = 100g is placed at bottom of a smooth inclined plane another charged particle of same charge and mass are placed r distance from first particle as shown in figure.
Now, at equilibrium
mgsin30° = Coulombs force = Kq²/r²
100 × 10⁻³ × 10 × 1/2 = 9 × 10⁹ × (2 × 10⁻⁶)²/r²
1/2 = 9 × 10⁹ × 4 × 10⁻¹²/r²
r² = 72 × 10⁻³
r² = 0.072
taking square root both sides,
r = 0.268 m or, 26.8 cm
Hence, charge B should placed at 26.8 cm from charge A