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25 ques plzz solve urgently A heavy particle is projected from a point on the horizontal at an angle 60 with horizontal with a speed of 10 m/s . Then radius of curvature of its path at the instant of its crossing the same horizontal is

25 ques plzz solve urgently
A heavy particle is projected from a point on the horizontal at an angle 60 with horizontal with a speed of 10 m/s . Then radius of curvature of its path at the instant of its crossing the same horizontal is 

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Grade:12

1 Answers

harshin nechooli
121 Points
5 years ago
Here here if you consider this a projectile motion at that particular instant has a circular motion then the centripetal force is provided by the perpendicular component of the gravitational force then we can equate the centripetal force and the portion of gravitation force which is perpendicular to the direction of the motion this will get that radius of curvature at that instant equal to velocity square divided by acceleration due to gravity hand at this particular condition we know that throughout the project and the horizontal velocity is unchanged and at the same height the vertical velocity will be same But in opposite direction does we get that the net velocity and this particular instance will be 10 metre per second and the perpendicular component of the acceleration due to gravity will be G cos theta that is Cos 60 so forget that radius of curvature is 20

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