2 particles of equal mass m at A and B connected by a rodAB lying on smooth horizontal table.An impulse J applied at A in plane of table and perpendicular to AB.Find velocity of particle A.

Question

Sayan Bhowmik · Answer

As we know the impulse is change in momentum so, J=p2-p1=2(mv)sin(angle). Here angle is 90°. So J=4mv. V=J/(4m)

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2 particles of equal mass m at A and B connected by a rodAB lying on smooth horizontal table.An impulse J applied at A in plane of table and perpendicular to AB.Find velocity of particle A.

2 particles of equal mass m at A and B connected by a rodAB lying on smooth horizontal table.An impulse J applied at A in plane of table and perpendicular to AB.Find velocity of particle A.

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2 particles of equal mass m at A and B connected by a rodAB lying on smooth horizontal table.An impulse J applied at A in plane of table and perpendicular to AB.Find velocity of particle A.

2 particles of equal mass m at A and B connected by a rodAB lying on smooth horizontal table.An impulse J applied at A in plane of table and perpendicular to AB.Find velocity of particle A.

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