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2 particles each of mass m and charge q are attached to the ends of a light rigid rod of length 2R. The rod is rotated at constant angular speed about perpendicular axis passing centre .Ratio of magnitude of magnetic moment and angular momentum about the centre is? please elucidate.

Radhika Batra , 11 Years ago
Grade 11
anser 1 Answers
Srishti sadhu

Last Activity: 7 Years ago

I=2q/t =(2q×w)÷(2π)Where w-angular speedI=qw/πMagnetic moment, M=IA =(qw/π)×(πR^2) =qwR^2Angular momentum, L=(2m)R^2×wM/L=qwR^2÷[(2m)R^2×w] =q÷(2m)

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