The 2.7 kg cylinder B and 1.8 kg wedge A are released from a bigger triangular wedge A wich is fixed. the angle of inclination of A is 30 degrees frm the horizontal.Assuming that cylinder rolls without sliding on the wedge and neglecting the fricyion between a and c determine(a) the acceleration of wedge(b) the angular acceleration of cylinder(g=10m/s^2)

Dear Aditya, 

acceleration of wedge=Mwgsin(30)/M=5m/s^2

a=linear acceleration,A=angular acceleration,f=friction,r=radius of cylinder,m=mass

a=rA, ma=mgsin(30)-f,fr=(1/2)mr²A, solving the three simultaneous equations we get a=(2/3)gsin(30)=10/3 m/s^2

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