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Grade 12Mechanics

Somebody made a giant spherical cavity in the earth such that the earth's center and a point in the surface are diametrically opposite. The someone drops a small ball from a small opening at the surface into the cavity. In how many minutes does the ball reach the center of earth???width=819

Profile image of sohan singh singh
16 Years agoGrade 12
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ApprovedApproved Tutor Answer0 Years ago

To determine how long it takes for a small ball to fall from the surface of the Earth to the center through a giant spherical cavity, we can analyze the situation using principles from physics, particularly gravitational motion. The scenario you described is quite fascinating and involves concepts of gravity and harmonic motion.

Theoretical Framework

When the ball is dropped into the cavity, it experiences gravitational force directed towards the center of the Earth. However, as it falls, the gravitational force acting on it changes due to the spherical symmetry of the Earth. According to the shell theorem, the gravitational force inside a uniform spherical shell is zero. Thus, only the mass of the Earth that is at a radius less than the ball's distance from the center contributes to the gravitational pull.

Gravitational Force Inside the Earth

As the ball descends, the effective gravitational force can be expressed as:

  • F = G * (m * M(r)) / r²

Here, G is the gravitational constant, m is the mass of the ball, M(r) is the mass of the Earth enclosed within radius r, and r is the distance from the center of the Earth to the ball. The mass M(r) can be calculated as:

  • M(r) = (4/3)πr³ρ

where ρ is the average density of the Earth. This means that the gravitational force acting on the ball is proportional to its distance from the center:

  • F = -k * r

where k is a constant that depends on the density of the Earth. This relationship indicates that the ball undergoes simple harmonic motion.

Time to Reach the Center

The time period for a simple harmonic oscillator is given by:

  • T = 2π√(m/k)

In our case, the ball will take a quarter of this period to reach the center from the surface. The average density of the Earth is approximately 5,500 kg/m³, and using the known values for the radius of the Earth (about 6,371 km), we can derive the time it takes for the ball to reach the center.

Calculating the Time

Using the formula for the time period and substituting the values, we find:

  • T = 2π√(R/g)

where R is the radius of the Earth and g is the acceleration due to gravity at the surface (approximately 9.81 m/s²). Plugging in these values gives:

  • T ≈ 2π√(6,371,000 m / 9.81 m/s²)

This results in a time period of about 84.5 minutes for a complete oscillation (from the surface to the center and back to the surface). Therefore, the time to reach the center is:

  • Time to center = T/4 ≈ 21.1 minutes

Final Thoughts

In summary, if a small ball is dropped into a giant spherical cavity that extends to the center of the Earth, it will take approximately 21.1 minutes to reach the center. This fascinating interplay of gravitational forces and harmonic motion showcases the beauty of physics in understanding the natural world.