 # A bird flies for 4 sec with a velocity of |t-2| m/s in a straight line where t=time in seconds .It covers a distance of Badiuddin askIITians.ismu Expert
148 Points
13 years ago

Dear Pratik

given

V= |t-2|

dx/dt = |t-2|

dx = |t-2|dt

oxdx  = o4|t-2|dt

x  = o2(2-t)dt  + 24(t-2)dt

=4

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13 years ago

how the step 5 come ?

6 years ago
givenV= |t-2| dx/dt = |t-2|dx = |t-2|dto∫xdx = o∫4|t-2|dt x = o∫2(2-t)dt + 2∫4(t-2)dt =4givenV= |t-2| dx/dt = |t-2|dx = |t-2|dto∫xdx = o∫4|t-2|dt x = o∫2(2-t)dt + 2∫4(t-2)dt =4givenV= |t-2| dx/dt = |t-2|dx = |t-2|dto∫xdx = o∫4|t-2|dt x = o∫2(2-t)dt + 2∫4(t-2)dt =4
6 years ago
As we know that
At t=0  u=2 m/s     and at t=2  v=0 m/s
Therefore by v=u+at   we get,
0=2+a2   =)     a=-1m/s2
And by s=vt-1/2at2  we get
S= 0×2-1/2×-1×2×2     =)     s=2m ---------------1
So the first part is complete and now the second part starts
We know that at  t=2seconds   u=0m/s     and at     t=4sec   v=2m/s so total time =2sec
So by v=u+at
2=0+a×2       =)         a=1m/s2
Now by  s=ut+1/2at2
s= 0×2+1/2×1×2×2      =)         s=2m      -------------2
So by adding 1 and 2
We get distance travelled by bird =2+2=4 meters
And thats the answer for those who find the calculus in this question difficult.  And also feel free to ask any doubts involved in this solution.

3 years ago

At t=0  u=2 m/s     and at t=2  v=0 m/s
Therefore by v=u+at   we get,
0=2+a2   =)     a=-1m/s2
And by s=vt-1/2at2  we get
S= 0×2-1/2×-1×2×2     =)     s=2m ---------------1
So the first part is complete and now the second part starts
We know that at  t=2seconds   u=0m/s     and at     t=4sec   v=2m/s so total time =2sec
So by v=u+at
2=0+a×2       =)         a=1m/s2
Now by  s=ut+1/2at2
s= 0×2+1/2×1×2×2      =)         s=2m      -------------2
So by adding 1 and 2
We get distance travelled by bird =2+2=4 meters