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Aditya Narayanan C Grade: 12
        Two blocks 2kg & 4kg are connected through a massless string. Coeff. of friction btw 2kg & ground is 0.4 & coeff. of friction btw 4kg & ground is 0.6. F1=10N is applied on 2kg block to the left and F2=20N is applied on 4kg block to the right. Calculate frictional force btw 4kg block and ground. (assume tension is zero before F1 and F2 is applied).Pls solve it.
8 years ago

Answers : (2)

Badiuddin askIITians.ismu Expert
147 Points

Dear Aditya

maximum friction force that can act in between 2 kg block and ground is =0.2*20 = 4

maximum friction force that can act in between 4 kg block and ground is =0.6*40 = 24

when 2kg block just start moving toward left

  equation on 2 kg block  

so 10 -T- 4 =0

      T =6

equation on 4 kg block

  calculate 20-T = 14

which is less than the max friction force for 4 kg block so it will remain in the state of rest

 and frictional force is 14 .

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8 years ago
Aditya Narayanan C
8 Points

i got the answer as 18 N. Briefly explain it.

8 years ago
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