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# If alpha is the angle of limiting friction, then the minimum force required to pull a block of mass m kept on the horizontal surface is?Ans mgsin(theta)

147 Points
11 years ago

Dear Nehal

Let a force F is applied on the block at an angel x from the horizontal

normal force will be N =mg - Fsinx

so Fcosx =μN

Fcosx =μ(mg - Fsinx)

F =μmg/(cosx +μsinx)

for minim F   , (cosx +μsinx)  will be maximum so  (cosx +μsinx)=√(1+μ2)

So  F min = μmg/√(1+μ2)

here μ = tanΘ

so F min = tanΘmg/√(1+tan2Θ)

=mgsinΘ

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