Question icon
Grade 12Mechanics

a particle moves with a decreasing speed along the circle of radius r so that at any moment its tang and centripetal acc are equal in magnitude.at t=0,its speed is u.plz time after which speed reduce to 0

Profile image of jauneet  singh
16 Years agoGrade 12
Answers icon

1 Answer

Profile image of Badiuddin askIITians.ismu Expert
16 Years ago

Dear jauneet

at any instant tangential acceleraion is given by = dV/dt

but this is equal to centripital acceleation which is given as = mV2/r

  so   dV/dt = V2/r

        dV/V2 = 1/r dt

    ∫dV/V2 =∫ 1/r dt

    -1/V = 1t/r + C

 apply condition at t=0 V=u

 so C=-1/c

equation become   -1/V = 1t/r + -1/u

                            1/V = 1/u  + t/r

                             1/V =(r+tu)/ur

                            V=ur/(r+tu)

                       so clearly after infinite time particle will come to rest

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin