Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

sir in an horizantal surface one block of mass 5 kg is placed on another block of 6 kg which is in contact with horizantal surface.there is no friction between between 6 kg block and horizantal surface.but there is a friction between 5 and 6 kg block ,cofficent of friction is 0.8 the block of mass m hanging from string freely which is in connected 2 mass of 5 kg frm other side.the max value of m if both blocks move relative to each other

sir in an horizantal surface one block of mass 5 kg is placed on another block of 6 kg which is in contact with horizantal surface.there is no friction between between 6 kg block and horizantal surface.but there is a friction between 5 and 6 kg block ,cofficent of friction is 0.8 the block of mass m hanging from string freely which is in connected 2 mass of 5 kg frm other side.the max value of m if both blocks move relative to each other

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear jauneet

 

7840-613_7662_untitled.JPG

acceleration of lower block a1 = .8N/6

acceleration of upper block a2 =(T-.8N)/5

 where N =5g   and T =mg

in limiting case a1 =a2

                   .8N/6  = (mg-.8N)/5

                   4N/6 = mg - .8N

                   4N =6mg -4.8N

                  6mg = 8.8 N

                  6mg =8.8*5g

                  m =22/3 kg

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free