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# Twp Point Masses m1 and m2 are joined by a weightless rod of length r. Calculate the moment of inertia of the system about an axis passing through the center of mass and perpendicular to the rod.Ans: (m1m2r^2)/(m1+m2)

147 Points
11 years ago

Dear Nehal Wani

Center of mass of the system from mass m1  =  (m1*0 + m2*r)/(m1+m2)

= m2 r/(m1+m2)

distance of COM from the mas m2  = [r- m2 r/(m1+m2)]

=m1 r/(m1+m2)

moment of inertia I = m1 [m2 r/(m1+m2)]2 + m1[m1 r/(m1+m2)]2

=m1 m2 r2/(m1+m2)

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