Grade 12Mechanics
1 Answer
Badiuddin askIITians.ismu Expert
Dear jauneet
let the natural length of spring is l
then F =kx
4 = k*a
k=4/a
and agian F=kx
5 = k(b-l)
5=4/a (b-l)
b-l = 5a/4
l= b-5a/4
let the length is x when tension is 9N
9 = 4/a (x-l)
9a/4 = x- (b-5a/4)
x = b-5a/4 +9a/4
=b-a
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