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A BODY OF MASS 10kg IS BEING ACTED APON BY A FORCE 3t2 AND AN OPPOSING CONSTANT FORCE OF 32N. THE INITIAL SPEED IS 10m/s THE VELOCITY OF BODY AFTER 5s IS=?
The forces on body are 32 N (opposing) and 3t2 ( in same dirn) along with ma ( driving force )
so, 32 = 3t2 + ma
32 = 3t2 + 10a
also V = u + at
at t = 5 from, both equations
V = 10 + (-4.3)*5
= -11.5 m/sec
It looks like body is decelerating, so it comes to rest after some if 32N is opposing force even before 5 seconds
P.S: I think thr is some wrong info in question
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regards
Ramesh
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