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A BODY OF MASS 10kg IS BEING ACTED APON BY A FORCE 3t 2 AND AN OPPOSING CONSTANT FORCE OF 32N. THE INITIAL SPEED IS 10m/s THE VELOCITY OF BODY AFTER 5s IS=?

A BODY OF MASS 10kg IS BEING ACTED APON BY A FORCE 3t2 AND AN OPPOSING CONSTANT FORCE OF 32N. THE INITIAL SPEED IS 10m/s THE VELOCITY OF BODY AFTER 5s IS=?

Grade:11

1 Answers

Ramesh V
70 Points
11 years ago

The forces on body are 32 N (opposing) and 3t2 ( in same dirn) along with ma ( driving force )

so, 32 = 3t2 + ma

32 = 3t2 + 10a

also V = u + at

at t = 5 from, both equations

V = 10 + (-4.3)*5

   = -11.5 m/sec

It looks like body is decelerating, so it comes to rest after some if 32N is opposing force even before 5 seconds

P.S: I think thr is some wrong info in question

     --

regards

Ramesh

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