A BODY OF MASS 10kg IS BEING ACTED APON BY A FORCE 3t2 AND AN OPPOSING CONSTANT FORCE OF 32N. THE INITIAL SPEED IS 10m/s THE VELOCITY OF BODY AFTER 5s IS=?

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A BODY OF MASS 10kg IS BEING ACTED APON BY A FORCE 3t²AND AN OPPOSING CONSTANT FORCE OF 32N. THE INITIAL SPEED IS 10m/s THE VELOCITY OF BODY AFTER 5s IS=?

vardaan kumar

16 Years agoGrade 11

1 Answer

Ramesh V

16 Years ago

The forces on body are 32 N (opposing) and 3t² ( in same dirn) along with ma ( driving force )

so, 32 = 3t² + ma

32 = 3t² + 10a

also V = u + at

at t = 5 from, both equations

V = 10 + (-4.3)*5

= -11.5 m/sec

It looks like body is decelerating, so it comes to rest after some if 32N is opposing force even before 5 seconds

P.S: I think thr is some wrong info in question

regards

Ramesh

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A BODY OF MASS 10kg IS BEING ACTED APON BY A FORCE 3t2 AND AN OPPOSING CONSTANT FORCE OF 32N. THE INITIAL SPEED IS 10m/s THE VELOCITY OF BODY AFTER 5s IS=?

vardaan kumar

1 Answer

Ramesh V

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