A PARTICLE IS MOVING IN THE X-Y PLANE. AT t=0, it is located on the origin o (0,0) and its VELOCITY IS V=a(3 1/2 i+j),WHERE a IS A +VE CONSTANT.ITS ACC Is CONSTANT AND IS f=-(i+j). IN ITS SUBSEQUENT MOTION t0 IT WILL CROSS X AXIS WHEN t=?

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A PARTICLE IS MOVING IN THE X-Y PLANE. AT t=0, it is located on the origin o (0,0) and its VELOCITY IS V=a(3 1/2 i+j),WHERE a IS A +VE CONSTANT.ITS ACC Is CONSTANT AND IS f=-(i+j). IN ITS SUBSEQUENT MOTION t>0 IT WILL CROSS X AXIS WHEN t=?

Badiuddin askIITians.ismu Expert · Answer

Dear Vardaan V y = a f y =-1 it cross the x axis when its y co -ordinate will be zero use h =V y t +1/2f y t 2 0= at -1/2t 2 t=0 or 2a t=o indicate initial position so after t=2a it will cross x axis Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Askiitians Experts Badiuddin

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A PARTICLE IS MOVING IN THE X-Y PLANE. AT t=0, it is located on the origin o (0,0) and its VELOCITY IS V=a(3 1/2 i+j),WHERE a IS A +VE CONSTANT.ITS ACC Is CONSTANT AND IS f=-(i+j). IN ITS SUBSEQUENT MOTION t>0 IT WILL CROSS X AXIS WHEN t=?

A PARTICLE IS MOVING IN THE X-Y PLANE. AT t=0, it is located on the origin o (0,0) and its VELOCITY IS V=a(3^1/2i+j),WHERE a IS A +VE CONSTANT.ITS ACC Is CONSTANT AND IS f=-(i+j). IN ITS SUBSEQUENT MOTION t>0 IT WILL CROSS X AXIS WHEN t=?

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A PARTICLE IS MOVING IN THE X-Y PLANE. AT t=0, it is located on the origin o (0,0) and its VELOCITY IS V=a(3 1/2 i+j),WHERE a IS A +VE CONSTANT.ITS ACC Is CONSTANT AND IS f=-(i+j). IN ITS SUBSEQUENT MOTION t>0 IT WILL CROSS X AXIS WHEN t=?

A PARTICLE IS MOVING IN THE X-Y PLANE. AT t=0, it is located on the origin o (0,0) and its VELOCITY IS V=a(31/2 i+j),WHERE a IS A +VE CONSTANT.ITS ACC Is CONSTANT AND IS f=-(i+j). IN ITS SUBSEQUENT MOTION t>0 IT WILL CROSS X AXIS WHEN t=?

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A PARTICLE IS MOVING IN THE X-Y PLANE. AT t=0, it is located on the origin o (0,0) and its VELOCITY IS V=a(3^1/2i+j),WHERE a IS A +VE CONSTANT.ITS ACC Is CONSTANT AND IS f=-(i+j). IN ITS SUBSEQUENT MOTION t>0 IT WILL CROSS X AXIS WHEN t=?