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Q A solid cylinder of mass m and radius r is rolling on a rough inclined plane of inclination θ. The coefficient of friction between the cylinder and incline is m. Then
(A) frictional force is always mmg cos θ
(B) friction is a dissipative force
(C) by decreasing θ, frictional force decreases
(D) friction opposes translation and supports rotation
Dear Mainak
N = mgcosx
maximum frictional force f= μN =μmgcosx
this friction force will not always act .it is the maximum possible frictional force.
a= (mgsinx -f)/m
for pure rollinr α =a/r
and torque f.r = mr2/2 α
f =ma/2
=m/2 (mgsinx -f)/m
f = mg/3 sinx
by decresing x frictional force decreses
so d option is correct
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