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Mainak Chakraborty Grade: Upto college level

9.     A solid sphere of mass M, radius R and having moment of inertia about an axis passing through the centre of mass as I, is recast into a disc of thickness t, whose moment of inertia about an axis passing through its edge and perpendicular to its plane remains I. Then, radius of the disc will be

        (A) 2R/√15

        (B) R√(2/15)

        (C) 4R/√15

        (D) R/4

8 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points

Dear Mainak

moment of inertia of solid sphere I =2/5 MR2

mass will remain conserve

 let the new radius is R1

so I = MR12/2 + MR12

       =3/2 MR12


so 3/2 MR12 =2/5 MR2

    R1 =2R/√15

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8 years ago
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