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a solid sphere is rolling purely on a rough horizontal plane(co.eff of kinetic friction is k)with the speed of center is U.it collides ineleastically with a smooth vertical wall at a certain moment ,the co eff of restitution is 1/2 the sphere will start rolling after time? detail explanation please

 


a solid sphere is rolling purely on a rough horizontal plane(co.eff of kinetic friction is k)with the speed of center is U.it collides ineleastically with a smooth vertical wall at a certain moment ,the co eff of restitution is 1/2 the sphere will start rolling after time?                                                                                                                    detail explanation please

Grade:Upto college level

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear akash


7175-2361_7662_untitled.JPG

linear acceleration a =kmg/m =kg

so V/14 = V/2 -at

   V/14 = V/2 - kgt

t = 3V/7kg

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