Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A sphere is pushed on a horizontal surface suffirough for pure rolling such aftermoving a little dist. it mounts on an inclined plane. It rises to a height h1 and h2 if the inclined plane is frictionless or suffi rough respectively.Then - 1)h1>h2 2)h1<h2 3)h1=h2 (The ans says h1<h2 as in h1 only translational KE is transformed to mgh1)

A sphere is pushed on a horizontal surface suffirough for pure rolling such aftermoving a little dist. it mounts on an inclined plane. It rises to a height h1 and h2 if the inclined plane is frictionless or suffi rough respectively.Then - 1)h1>h2 2)h1

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear Aveek

let the initial velocity of sphere is U

case 1 :  sphere is rolling

 acceleration along the inclind plane a= gsinθ/[1+ I/mr2]

I = 2/5 mr2

so a = 5/7 gsinθ

 now equation  V2 =U2- 2aS

  S=U2/2a

 so  h2 =S sinθ = 0.7 U2/2g

 case 2:  sphere is not rolling

  a =gsinθ

and h1=Ssinθ = 0.5U2/2g

h2 > h1

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed
solution very  quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free