0

Guest

Courses New

A sphere is pushed on a horizontal surface suffirough for pure rolling such aftermoving a little dist. it mounts on an inclined plane. It rises to a height h1 and h2 if the inclined plane is frictionless or suffi rough respectively.Then - 1)h1>h2 2)h1<h2 3)h1=h2 (The ans says h1<h2 as in h1 only translational KE is transformed to mgh1)

A sphere is pushed on a horizontal surface suffirough for pure rolling such aftermoving a little dist. it mounts on an inclined plane. It rises to a height h1 and h2 if the inclined plane is frictionless or suffi rough respectively.Then - 1)h1>h2 2)h1

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
148 Points
14 years ago

Dear Aveek

let the initial velocity of sphere is U

case 1 :  sphere is rolling

 acceleration along the inclind plane a= gsinθ/[1+ I/mr2]

I = 2/5 mr2

so a = 5/7 gsinθ

 now equation  V2 =U2- 2aS

  S=U2/2a

 so  h2 =S sinθ = 0.7 U2/2g

 case 2:  sphere is not rolling

  a =gsinθ

and h1=Ssinθ = 0.5U2/2g

h2 > h1

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed
solution very  quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More