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Find the position of centre of mass of the lined section shown in fig.
Dear neeraj
let the mass of each portion is m
first find out the COM of individual portion
COM of the upper horizontal portion = (a/2 ,2a)
COM of the upper vertical portion = (a ,3a/2)
COM of the lower horizontal portion = 3a/2 ,a)
COM of the lower vertical portion = (2a ,a/2)
now the COM of the whole
x' = {m*a/2 + m *a + m*3a/2 + m*2a }/4m
= 5a/4
y' = {m*2a + m *3a/2 + m*a + m*a/2 }/4m
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