a boy whirls the stone in horizontal circle of radius 1.5m....at a height of 2 m,,,,,above the ground..the string breaks and the stone flies off horizontally and strikes the ground after travellin a hori distance of 10m,,,,find its centripeal acceleration..

Dear shivanshi

It is a question of projectile motion

let the horizontal velocity of stone when string breaks is =V

verticale velocity is zero

let  time taken to reach the ground is t

equation for verticle motion

 h=1/2gt²

2=1/2 * 10 * t²

t= √.4

so equation for horizontal motion

S =Vt

10 = V *√.4

V= 15.81 m/sec

so centripital acceleration = V²/r

                                      = (15.81)² /1.5

                                      =166.64 m/sec²

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