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# an open link chain is there and each link is of mass .1 kg........it is being pulled against gravity in vertically upward direction....find the force on the link1(the lowest one)by link 2...by 3 on 2......by 4 on 3.......by 4 on 5..........

147 Points
11 years ago

Dear shivanshi

Let the force F is aplied on the link and it is moving with and acceleration a.

and  chain has total 1 link

F- n*1*g =na

a= F/n -g

let N1 force is applied by link 2 on link 1

N1- 1*g = 1*a

N1 = g+a

=F/n

let N2 force is applied by link 3 an link 2

N2 -2*g =2*a

N2 = 2(g+a)

=2F/n

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