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# a particle starts from t=0 with a velocity of 8j and moves inthe xy plane with a constant acceleraton of 4i+2j......at the moment when its x coordinate is 29m,what is its speed?y coordinate?

147 Points
11 years ago

Dear shivanshi

ux = 0

uy= 8 m/sec

ax = 4 m/sec2

ay = 2 m/sec2

use formula  Sx= ux t + 1/2 ax t2

29 = 0 + 1/2 *4 *t2

t= √(29/2)  sec

Vx = Ux  + ax t

= 4√(29/2)

Vy =Uv + ay t

=8 + 2√(29/2)

speed  =[Vx2 +Vy2]1/2

y co ordinate Sy=Uy t + 1/2 ayt2

=8√(29/2)  +29/2

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