an electron movigalong x axis has a position given by x= 16te to the power -t(only e has been raised to the power -e)...where t is time in sec...how far is the electron from the origin when it momentarily stops?

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Badiuddin askIITians.ismu Expert · Answer

Dear shivanshi x= 16te -t v=dx/dt =16 e-t (1-t) put v=0 16 e-t (1-t) =0 t=1 sex so x at t=1 is =16e -1 Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards, Askiitians Experts Badiuddin

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an electron movigalong x axis has a position given by x= 16te to the power -t(only e has been raised to the power -e)...where t is time in sec...how far is the electron from the origin when it momentarily stops?

an electron movigalong x axis has a position given by x= 16te to the power -t(only e has been raised to the power -e)...where t is time in sec...how far is the electron from the origin when it momentarily stops?

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