Guest

A mass of 100 gm is tied to one end of a string 2m long The body is revolving in a horizontal circle making an maximum of 200 revolutions per min The other end of the string is fixed at the centre of the circle of revolution The max tension that the string can bear

A mass of 100 gm is tied to one end of a string 2m long The body is revolving in a horizontal circle making an maximum of 200 revolutions per min The other end of the string is fixed at the centre of the circle of revolution The max tension that the string can bear

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
148 Points
14 years ago

Dear pallvi

m =200 gm =.2kg

r = 2m

ω=200 rev/min  =20 ∏/3 rad /sec

 

 centrifugal force F = mω2r

                           = .2 * (20 ∏/3)2 * 2

                           =175.45 N

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

Think You Can Provide A Better Answer ?

ASK QUESTION

Get your questions answered by the expert for free