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A 1 kg stone at the end of 1m long string is whriledin a vertical circle at a constant speed of 4m/s the tension in the string is 6 N when the stone is at
Dear pallavi T = mv2 /r + mgcosx 6 = 1*16/1 + 1*10 cosx cosx=-1 x=180 so particle will be at top most position. Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
Dear pallavi
T = mv2 /r + mgcosx
6 = 1*16/1 + 1*10 cosx
cosx=-1
x=180
so particle will be at top most position.
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
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