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a 40kg girl and an 8.4 kg sled are connected and are on frictionless ice of a frozen lake,15 m apart and the girl exerts 5.2N on the rope...how far from the girl's position do they meet?
Dear shivanshi
girl exerts 5.2N on the rope
so rope also exerts 5.2 N force on girl .and same force also exert ny rope at the other end to sled
acceleration of girl = 5.2/40 =.13 m/sec2
acceleration of sled = 5.2 /8.4 =.62 m/sec2
relative acceleration of girl w.r.t sld =a = .62 + .13 =.75 m/sec2
let time taken to meet is t
S=1/2 a t2
15 =1/2 * .75 * t2
t2 =40
distance travel by girl in this time
S=1/2* 5.2/40 * 40
=5.2/2 =2.6 m answer
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