a 40kg girl and an 8.4 kg sled are connected and are on frictionless ice of a frozen lake,15 m apart and the girl exerts 5.2N on the rope...how far from the girl's position do they meet?

Dear shivanshi

girl exerts 5.2N on the rope

so rope also exerts 5.2 N force on girl .and same force also exert ny rope at the other end to sled

acceleration of girl = 5.2/40  =.13 m/sec²

acceleration of sled = 5.2 /8.4 =.62 m/sec²

relative acceleration of girl w.r.t sld  =a = .62 + .13 =.75 m/sec²

let time taken to meet  is t

S=1/2 a t²

15 =1/2 * .75 * t²

 t² =40

distance travel by girl in this time

S=1/2* 5.2/40 * 40

   =5.2/2 =2.6 m answer

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