Badiuddin askIITians.ismu Expert
Last Activity: 15 Years ago
Dear shivanshi
girl exerts 5.2N on the rope
so rope also exerts 5.2 N force on girl .and same force also exert ny rope at the other end to sled
acceleration of girl = 5.2/40 =.13 m/sec2
acceleration of sled = 5.2 /8.4 =.62 m/sec2
relative acceleration of girl w.r.t sld =a = .62 + .13 =.75 m/sec2
let time taken to meet is t
S=1/2 a t2
15 =1/2 * .75 * t2
t2 =40
distance travel by girl in this time
S=1/2* 5.2/40 * 40
=5.2/2 =2.6 m answer
Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best.
Regards,
Askiitians Experts
Badiuddin