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for a womans volleyball the top of the net is 22.4 m above the ground.and the court measures 9m by 9m on each sideof the net.using a jump throwa player a player strikes the ball at a point 3m above the floor and a horizontal distance of 8m from the net.initial vel of the ball is horizontal.what min magnitude must the initial vel have so as to clear the net??

for a womans volleyball the top of the net is 22.4 m above the ground.and the court measures 9m by 9m on each sideof the net.using a jump throwa player a player strikes the ball at a point 3m above the floor and a horizontal distance of 8m from the net.initial vel of the ball is horizontal.what min magnitude must the initial vel have so as to clear the net??

Grade:11

3 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear shivanshi

Hight of the net is 22.4 m

and it has given a horizontal velocity at a hight 3 m .then it will never cross the net.

I think question has some error check it and post agian.

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Shreyans Sharma
33 Points
11 years ago

Is the answer 20.32m/s

Shreyans Sharma
33 Points
11 years ago

Dear Shivanshi,

When you get the solution please forward it to me. It wud be reeally kind of you.

Thanks

Shreyans

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