for a womans volleyball the top of the net is 22.4 m above the ground.and the court measures 9m by 9m on each sideof the net.using a jump throwa player a player strikes the ball at a point 3m above the floor and a horizontal distance of 8m from the net.initial vel of the ball is horizontal.what min magnitude must the initial vel have so as to clear the net??

Dear shivanshi

Hight of the net is 22.4 m

and it has given a horizontal velocity at a hight 3 m .then it will never cross the net.

I think question has some error check it and post agian.

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Badiuddin

Is the answer 20.32m/s

Dear Shivanshi,

When you get the solution please forward it to me. It wud be reeally kind of you.

Thanks

Shreyans