Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
dear chilukuri
velocity of teniss when it just about to touch the ground =√2g*4
=√8g or -√8g j
velocity of teniss ball when it just about to leave the ground after collison =√2g*2
=√4g or √4g j
avg acceleration = change in velocity /total time
=(√4g j +√8g j)/12* 10-3
=(√2 + 1)√g *103/6 m/sec2
Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best.
Regards,
Askiitians Experts
Badiuddin