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Find the acceleration of mass M in the situation of figure. The coefficient of friction between the two blocks is µ1 and that between the bigger block and the ground is µ2.
dear jayesh
let normal reaction between two block is N1 ,and the normal reaction between biggger block and ground in N2
for smaller block
so mg - T -μ1N1 =m2a.....1
N1=ma .............2
for bigger block
N2 =Mg +μ1N1 +T
or N2=Mg + mg-2ma (from equation 1).......3
and T +T -N1 -μ2N2=Ma
2T -ma -μ2(Mg +mg-2ma) =Ma ........4
put value of T from equation 1
2(mg -μ1ma-2ma) -ma -μ2(Mg +mg-2ma) =Ma
solve for a
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