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A heavy box of mass 20 kg is pulled on a horizontal surface.If the coefficient of kinetic friction between the box and the horizontal surface is 0.25 find the force of friction exerted by the horizontal forces on the box

A heavy box of mass 20 kg is pulled on a horizontal surface.If the coefficient of kinetic friction between the box and the horizontal surface is 0.25 find the force of friction exerted by the horizontal forces on the box

Grade:12

2 Answers

Askiitians Expert Bharath-IITD
23 Points
11 years ago

Dear Pallavi,

The kinetic friction generated due the horizontal forces on the box is given by the formula Fk= μkmg = 0.25 * 20 * 9.8 N = 49N

 

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Shankararama Sharma
35 Points
10 years ago

While in motion only the kinetic friction acts. f=uN.

                                                               f=umg

                                                                =0.25*20*9.8

                                                                =49N

so the friction exerted by the horizontal forces is 49N.

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