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# A stone is thrown vertically upwards. When particle is at a height half of its maximum height, its speed is 10m/s; then the maximum height attained by the particle is: [g = 10m/s2]         (a)    8 m         (b)    10 m         (c)    15 m         (d)    20 m

7 years ago

(b)
Let h be maximum height to be attained by stone.
Velocity with which particle is thrown
u= √2gh
v^2=u^2+2gh
when H=h/2,u= √2gh,v=10 m/s   g=-g
v^2-u^2=  2gH

2gh-100=  2g h/2
2 g  h/2  =100

h =10 m.

2 years ago
V^2 - u^2 = 2aS
10^2 - u^2 = -2gH/2
-gH = 100 - u^2
-gu^2 / (2g) = 100 - u^2
u^2 / 2 = u^2 - 100
100 = u^2 / 2
u^2 = 200
H = u^2 / (2g)
= 200 / (2 × 10)
= 10 m
Maximum height attained by it is 10 m