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300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g = 10 m/s2, work done against friction is

(a) 1001

(b) Zero

(c) 1000 J

(d) 200 J

Kevin Nash , 12 Years ago
Grade upto college level
anser 2 Answers
Simran Bhatia

(a)

Work done against gravity = mg sin q × d

= 2 × 10 × 10    (d sinq = 10)

= 200 J

Actual work done = 300 J

Work done against friction = 300 - 200 = 100 J

Last Activity: 12 Years ago
Muntazir
Loss in potential energy =mgh =2×10×10=200j gain in kinetic enegy =work done=300j work against friction =300-200=100
Last Activity: 7 Years ago
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