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Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is (taking g = 10 m/s 2 ) (a) 30m (b) 40m (c) 12m (d) 20m



Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is (taking g = 10 m/s2) 


(a)    30m


(b)    40m


        (c)    12m


(d)    20m


Grade:11

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
7 years ago

(b)
Here u = 72 km/h = 20 m/s; v = 0;
a =- ?g = -0.5 × 10 =-5m/s2
As v2 = u1 + 2as,
? s=  ((v^2- u^2 ))/2a  =((0- (20)^2)/(2× (-5) )=40 m

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