Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A particle travels in a straight line such that for a short time 2s<t<6s, its motion is described by v=(4/a)m/s, where 'a' is in m/s2. If v=6m/s when t=2sec, determine the particle's acceleration when t=3 sec.

147 Points
11 years ago

Dear Chilukuri

V=4/a

Va =4

V dv/dt =4

intigrate

V2/2 =4t +c1

V2 =8t +c

apply given condition

36 =16 +c

c= 20

so

V2 =8t +20

velocity at t=3 sec

V = √44

so acceleration  a=4/v  =4/√44

=2/√11 m/sec2

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the

answer and detailed solution very quickly.

All the best.

Regards,