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```        A particle moves in x-y plane. At time t=0, particle is at (1m,2m) and has vel.(4i+6j)m/s. At t=4sec, particle  reaches (6m,4m) and has velocity (2i+10j)m/s. In the given time interval, find:
a)Avge.Vel=?
b)Avge. Acceleration=?
c)From,given data, find avge.Speed=?```
8 years ago

147 Points
```										Dear Chilukuri
Total displace ment = ( (6-1)2 + ( 4-2)2 )1/2
= √29  m
total time     = 4 sec
change in velocity = |(2i+10j) -(4i +6j) |  =√20

so avg velocity = total displacement /total time
=√29 /4  m/sec
avg acceleration      = change in velocity /time interval
= √20 /4  =√5 /2  m/sec2
since path of the particle is not know only initial and final position is known so avg speed can not be calculated with this given data

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8 years ago
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