A particle moves in x-y plane. At time t=0, particle is at (1m,2m) and has vel.(4i+6j)m/s. At t=4sec, particle reaches (6m,4m) and has velocity (2i+10j)m/s. In the given time interval, find:a)Avge.Vel=?b)Avge. Acceleration=?c)From,given data, find avge.Speed=?

Dear Chilukuri

Total displace ment = ( (6-1)² + ( 4-2)² )^1/2

                                            = √29  m

total time     = 4 sec

change in velocity = |(2i+10j) -(4i +6j) |  =√20

so avg velocity = total displacement /total time

                     =√29 /4  m/sec

avg acceleration      = change in velocity /time interval

                            = √20 /4  =√5 /2  m/sec2

since path of the particle is not know only initial and final position is known so avg speed can not be calculated with this given data

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