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A particle moves in x-y plane. At time t=0, particle is at (1m,2m) and has vel.(4i+6j)m/s. At t=4sec, particle reaches (6m,4m) and has velocity (2i+10j)m/s. In the given time interval, find:
a)Avge.Vel=?
b)Avge. Acceleration=?
c)From,given data, find avge.Speed=?
Dear Chilukuri
Total displace ment = ( (6-1)2 + ( 4-2)2 )1/2
= √29 m
total time = 4 sec
change in velocity = |(2i+10j) -(4i +6j) | =√20
so avg velocity = total displacement /total time
=√29 /4 m/sec
avg acceleration = change in velocity /time interval
= √20 /4 =√5 /2 m/sec2
since path of the particle is not know only initial and final position is known so avg speed can not be calculated with this given data
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