a rod of mass m and length 2R is fixed along the diameter of ring of same mass m and radius R is rolling without slipping with a speed v along x axis. find angular momentum about z axis.

Question

Arun Kumar · Answer

angular momentum equal to I.omega omega=V/R and I = m((2R)^2)/12+(mR^2)/2 we are taking moment of inertia about centre axis

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a rod of mass m and length 2R is fixed along the diameter of ring of same mass m and radius R is rolling without slipping with a speed v along x axis. find angular momentum about z axis.

a rod of mass m and length 2R is fixed along the diameter of ring of same mass m and radius R is rolling without slipping with a speed v along x axis. find angular momentum about z axis.

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a rod of mass m and length 2R is fixed along the diameter of ring of same mass m and radius R is rolling without slipping with a speed v along x axis. find angular momentum about z axis.

a rod of mass m and length 2R is fixed along the diameter of ring of same mass m and radius R is rolling without slipping with a speed v along x axis. find angular momentum about z axis.

1 Answers

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Other Related Questions on Mechanics

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