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# A particle is moving eastwards with a velocity of 5m/s.In 10sec the velocity changes to 5m/s northwards.The average acceleration inthis time is

147 Points
11 years ago

Dear pallavi

Vi =5i

Vf=5j

Avg acceleration =|(Vf -Vi)|/10

=|5j-5i)|10

=1/√2 m/s2

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ASh
62 Points
3 years ago
Dear pallavi

Vi =5i

Vf=5j

Avg acceleration =|(Vf -Vi)|/10

=|5j-5i)|10=1/√2 m/s2

SEKHAR
13 Points
3 years ago
initial velocity =u=5m/s towards East
Final velocity =v=5m/s towards North
Resultant velocity =R=dv=(52+52)1/2=7.071
Time =dt=10 sec
Now acceleration =dv/dt=7.071/10=0.7071
one year ago
Dear student,

Vi =5i

Vf=5j

Avg acceleration = |(Vf -Vi)|/10

= |5j-5i)|10

= 1/√2 m/s2

Hope it helps.

Thanks and regards,

Kushagra