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A particle is moving eastwards with a velocity of 5m/s.In 10sec the velocity changes to 5m/s northwards.The average acceleration inthis time is

pallavi pradeep bhardwaj , 14 Years ago
Grade 12
anser 4 Answers
Badiuddin askIITians.ismu Expert

Last Activity: 14 Years ago

Dear pallavi

Vi =5i

Vf=5j

Avg acceleration =|(Vf -Vi)|/10

                        =|5j-5i)|10

                        =1/√2 m/s2

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Badiuddin

ASh

Last Activity: 6 Years ago

Dear pallavi 


Vi =5i

Vf=5j 

Avg acceleration =|(Vf -Vi)|/10

=|5j-5i)|10=1/√2 m/s2

 

SEKHAR

Last Activity: 6 Years ago

initial velocity =u=5m/s towards East 
Final velocity =v=5m/s towards North
Resultant velocity =R=dv=(52+52)1/2=7.071
Time =dt=10 sec
Now acceleration =dv/dt=7.071/10=0.7071

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the attached solution to your problem.
 
Vi =5i

Vf=5j

Avg acceleration = |(Vf -Vi)|/10

                        = |5j-5i)|10

                        = 1/√2 m/s2

Hope it helps.

Thanks and regards,

Kushagra

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