A blind person of walking of 10 step in one dirction each of lenght 80cm.turns randomly to left or right.after walking ''n'' steps the maximum displacement oe peson is 16root2m.then the ''n'' is..

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rishabh · Answer

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Khandavalli Satya Srikanth · Answer

16sqrt(2)=sqrt(8 2 +(n*0.8) 2 ) n=26.4. He walks approximately 26 steps.

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A blind person of walking of 10 step in one dirction each of lenght 80cm.turns randomly to left or right.after walking ''n'' steps the maximum displacement oe peson is 16root2m.then the ''n'' is..

A blind person of walking of 10 step in one dirction each of lenght 80cm.turns randomly to left or right.after walking ''n'' steps the maximum displacement oe peson is 16root2m.then the ''n'' is..

2 Answers

16sqrt(2)=sqrt(8² +(n*0.8)² )

n=26.4.

He walks approximately 26 steps.

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A blind person of walking of 10 step in one dirction each of lenght 80cm.turns randomly to left or right.after walking ''n'' steps the maximum displacement oe peson is 16root2m.then the ''n'' is..

A blind person of walking of 10 step in one dirction each of lenght 80cm.turns randomly to left or right.after walking ''n'' steps the maximum displacement oe peson is 16root2m.then the ''n'' is..

2 Answers

16sqrt(2)=sqrt(82 +(n*0.8)2 )

n=26.4.

He walks approximately 26 steps.

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16sqrt(2)=sqrt(8² +(n*0.8)² )