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Wind blows along S-E direction with a speed of 5m/s.A plstic bag is thrown with a velocity of 5(i+2j+k) m/s from a building 10m high then the position vector of the point where the bag lends off on the earth will be(x,y and z axes respectively point along east,north and vertically up directions, the point of projection being origin)_____________
Dear sindhuja
velocity of wind =5/√2 (i-j)
velocity of plastic bag =5(i+2j+k)
resultant velocity of plastic bag =5(i+2j+k) +5/√2 (i-j)
=(5+5/√2)i +(10-5/√2)j +5k
time take to reach the ground
10=5t +1/2 *10* t2
t2 +t -1=0
t=1 sec
in this time distance travel in x direction =(5+5/√2) *1 =5+5/√2
in this time distance travel in y direction =(10-5/√2) *1 =10-5/√2
so position vector =(5+5/√2)i +(10-5/√2)j +0k
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