2 bodies are projected vertically upwards from one point with the same initial velocity vo. The second body is projected to seconds after the first.How long after will the bodies meet?
Dear Chilukuri
let at hight h and after t second from the projection of second body both bodies meet
since first body projected t0 second earlier so
h=v(t+t0) -1/2 *g *(t+t0)2
for second body
h=vt-1/2 *g *t2
equate both
v(t+t0) -1/2 *g *(t+t0)2 = vt-1/2 *g *t2
simplify
2vt0/g =(2t+t0)t0
t={2v/g -t0}/2
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