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A car moving with const. acceleration covered distance between 2 points 60m apart in 6 sec. Its speed as it passes 2nd point was 15 m/s.
1)At what prior distance from the first point was the car at rest?
2)Plot graph between s and t between v and t, starting from rest ?
Plz.Explain...
Dear Chilukuri
let the velocity of car at first point is v
and at x prior distance from first point car was in the rest.
motion between first and second point
15=v +a*6 ......................1
and
60 =v(6) +1/2 *a* (6)2
10=v +3a ..........................2
solve equation 1 and 2
a=5/3
v=5
now motion between fron point of rest to first point
52 =02 +2*a*x
x=15/4 m
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