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A body falling from a vertical height of 10m pierces through a distance of 1m in sand. It faces an average retardation in sand equal to? [Answer is in terms of g i.e acceleration due to gravity ]

A body falling from a vertical height of 10m pierces through a distance of 1m in sand. It faces an average
retardation in sand equal to?

[Answer is in terms of g i.e acceleration due to gravity ]

Grade:

2 Answers

shubham sharma
27 Points
10 years ago

Ans is 10g.

Just find vel. With which it strikes down and then for rest motion apply equations of motions.

Nikita Gidwani
11 Points
6 years ago
u=0g=10Velocity just before piercing in sand v^2-0=2*10*9v^2=180m/sRetardation experienced in sand 0-180=2*(-a)*1a=90=9*10=9gHence retardation=9g

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