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A body falling from a vertical height of 10m pierces through a distance of 1m in sand. It faces an average retardation in sand equal to? [Answer is in terms of g i.e acceleration due to gravity ]

Swati , 12 Years ago
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anser 2 Answers
shubham sharma

Ans is 10g.

Just find vel. With which it strikes down and then for rest motion apply equations of motions.

Last Activity: 12 Years ago
Nikita Gidwani
u=0g=10Velocity just before piercing in sand v^2-0=2*10*9v^2=180m/sRetardation experienced in sand 0-180=2*(-a)*1a=90=9*10=9gHence retardation=9g
Last Activity: 8 Years ago
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