Vishal Gupta
Last Activity: 8 Years ago
v=u+atu=+vv=-3va=-g=>-4v=-gt=>t=4v/gtime for velocity to be -v= 2v/gSo 4v/g-2v/g time is taken to cover the tower with a velocity v downwardss= -v*(2v/g) +1/2*(-g)*(2v/g)*(2v/g)=> s= -2(v^2)/g -1/2*(4(v^2)/g)=> s=-2(v^2)/g -(2(v^2)/g)=>s=-4(v^2)/gSo ht of tower is 4(v^2)/g