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A small body is projected up a rough(coefficent of friction=0.5)inclined plane,(inclined angle=60 degree)with a speed 10 metre per second. How far along the plane it moves up before coming to rest?? g=10 ms^-2

Manish Singh , 12 Years ago

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1 Answers

Kunjal sheth

We know that work done by all forces = change in K.E.----1

And work done = net force x displacement

Therefore

W.D. = (umgcos@ +mgsin@)x displacement

By 1

(umgcos@ +mgsin@)x displacement (s)=(1/2)mvv

(umgcos(60) + mgsin(60)) x s=(1/2)m(100)

((1/2)(10)(1/2)+(10)(√3/2)) x s =50

S= (20)/2√3+1

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Mechanics> work-energy-power...

A small body is projected up a rough(coefficent of friction=0.5)inclined plane,(inclined angle=60 degree)with a speed 10 metre per second. How far along the plane it moves up before coming to rest?? g=10 ms^-2

Manish Singh , 12 Years ago

Kunjal sheth

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