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A particle is moving along a straight line through a fluid medium such that its speed is measured as v = (2t) m/s, where t is in seconds. If it is released from rest at s = 0, determine its positions and acceleration when t = 5 s. A. s = 25 m, a = 2 m/s2 B. s = 23m, a = 18 m/s2 C. s = 18 m, a = 2 m/s2 D. s = 22 m, a = 9 m/s2


A particle is moving along a straight line through a fluid medium such that


its speed is measured as v = (2t) m/s, where t is in seconds. If it is released


from rest at s = 0, determine its positions and acceleration when t = 5 s.


A. s = 25 m, a = 2 m/s2


B. s = 23m, a = 18 m/s2


C. s = 18 m, a = 2 m/s2


D. s = 22 m, a = 9 m/s2


Grade:Upto college level

1 Answers

India VK
42 Points
8 years ago

Integrate v = 2t to get 

s = t^2 + const.

Put t = 0 to get constant = 0. Now find s at t = 5s

Differenciate v = 2t to get

a = 2

which is constant with time.

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