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A man weighs 100 kg and stands in an elevator which is 25 kg which is connected to a pulley and the other end of the rope is in the man''s hand. When the man pulls the rope, he exerts a force of 450N on the frame/elevator. What is the acceleration of the frame/elevator?

A man weighs 100 kg and stands in an elevator which is 25 kg which is connected to a pulley and the other end of the rope is in the man''s hand. When the man pulls the rope, he exerts a force of 450N on the frame/elevator. What is the acceleration of the frame/elevator?

Grade:10

5 Answers

mohit yadav
54 Points
8 years ago

54

Syed Misbahuddin Husain
33 Points
8 years ago

a = 6.4 m/s2

shubham sharma
27 Points
8 years ago

Ans . Should be - 1.33 m/s''2

Eq. Of man will be T-550=100a

And of lift will be T-650=25a

Solve this for ''a''

 

Naman Aggarwal
12 Points
7 years ago
26.133 m/s^2 upwards!
 
somi waseem zaidi
18 Points
7 years ago
-10

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