aprojectile is projected with speed u at an angle 60 with horizantal from foot of the inclined plane. if the projectile hits the inclined plane horizontally,the range on inclined plane is

Dear akash

projectile hit the plane horizontaly ,it means it hit at its hihest point

H= u²sin²60 /2g

and R =u²sin120/g

or R/2 = u²sin120/2g

tan A =H/(R/2)   where A is the angel of plane

        =tan60 /2

         =√3/2

so range on incline plane =H/sinA

 

Put the value of H and SinA  you will get the result

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