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Two blocks of masses 2Kg & 1Kg are tied to a string which passess over a light pulley.Initially the masses are held at rest on the same horizontal line.Find the distance travelled by centre of mass in 2 sec__________
Dear sindhuja p
acceleration of masses is given by a=(m2-m1)g/(m2+m1)
=g/3
1 kg moves in upword direction =1/2 a t2
=1/2 *g/3 *4
=2g/3
2kg moves in downward direction =1/2 a t2
Now center of mass ={1*2g/3 +2*(-2g/3)}/(1+2)
=-2g/9
so center of mass 2g/9 m in downward direction
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