Two blocks of masses 2Kg & 1Kg are tied to a string which passess over a light pulley.Initially the masses are held at rest on the same horizontal line.Find the distance travelled by centre of mass in 2 sec__________

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Badiuddin askIITians.ismu Expert · Answer

Dear sindhuja p

acceleration of masses is given by a=(m2-m1)g/(m2+m1)

=g/3

1 kg moves in upword direction =1/2 a t²

=1/2 *g/3 *4

=2g/3

2kg moves in downward direction =1/2 a t²

=2g/3

Now center of mass ={1*2g/3 +2*(-2g/3)}/(1+2)

=-2g/9

so center of mass 2g/9 m in downward direction

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Two blocks of masses 2Kg & 1Kg are tied to a string which passess over a light pulley.Initially the masses are held at rest on the same horizontal line.Find the distance travelled by centre of mass in 2 sec__________

Two blocks of masses 2Kg & 1Kg are tied to a string which passess over a light pulley.Initially the masses are held at rest on the same horizontal line.Find the distance travelled by centre of mass in 2 sec__________

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